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A350386
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a(n) is the sum of the even exponents in the prime factorization of n.
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10
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0, 0, 0, 2, 0, 0, 0, 0, 2, 0, 0, 2, 0, 0, 0, 4, 0, 2, 0, 2, 0, 0, 0, 0, 2, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 4, 0, 0, 0, 0, 0, 0, 0, 2, 2, 0, 0, 4, 2, 2, 0, 2, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 2, 6, 0, 0, 0, 2, 0, 0, 0, 2, 0, 0, 2, 2, 0, 0, 0, 4, 4, 0, 0, 2, 0, 0, 0, 0, 0, 2, 0, 2, 0, 0, 0, 0, 0, 2, 2, 4, 0, 0, 0, 0, 0
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OFFSET
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1,4
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COMMENTS
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a(n) is the number of prime divisors of n, counted with multiplicity, with an even exponent in the prime factorization of n.
All the terms are even by definition.
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LINKS
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FORMULA
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Additive with a(p^e) = e if e is even and 0 otherwise.
a(n) = 0 if and only if n is an exponentially odd number (A268335).
a(n) = A001222(n) if and only if n is a positive square (A000290 \ {0}).
Asymptotic mean: lim_{m->oo} (1/m) * Sum_{k=1..m} a(k) = Sum_{p prime} 2*p/((p-1)*(p+1)^2) = 0.7961706018...
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MATHEMATICA
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f[p_, e_] := If[EvenQ[e], e, 0]; a[1] = 0; a[n_] := Plus @@ f @@@ FactorInteger[n]; Array[a, 100]
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PROG
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(Python)
from sympy import factorint
def a(n): return sum(e for e in factorint(n).values() if e%2 == 0)
(PARI) a(n) = my(f=factor(n)); sum(k=1, #f~, if (!(f[k, 2] % 2), f[k, 2])); \\ Michel Marcus, Dec 29 2021
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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