|
|
A348415
|
|
Numbers k such that k and k+1 have the same denominator of the harmonic means of their divisors.
|
|
2
|
|
|
12, 88, 180, 266, 321, 604, 4277, 4364, 8632, 15861, 18720, 28461, 47613, 63546, 97412, 98907, 135078, 137333, 154132, 179621, 185776, 192699, 203709, 265489, 284883, 344217, 383466, 517610, 604197, 876469, 1089604, 1277518, 1713865, 1839123, 1893268, 2349390
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
The common denominators of k and k+1 are 7, 45, 91, 30, 36, 133, 96, 637, ...
Can 3 consecutive numbers have the same denominator of harmonic mean of divisors? There are no such numbers below 10^10.
|
|
LINKS
|
|
|
EXAMPLE
|
12 is a term since the harmonic means of the divisors of 12 and 13 are 18/7 and 13/7, respectively, and both have the denominator 7.
|
|
MATHEMATICA
|
dh[n_] := Denominator[DivisorSigma[0, n]/DivisorSigma[-1, n]]; Select[Range[10^6], dh[#] == dh[# + 1] &]
|
|
PROG
|
(PARI) f(n) = my(d=divisors(n)); denominator(#d/sum(k=1, #d, 1/d[k])); \\ A099378
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|