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A343572
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a(n) = ceiling((16^n)*Sum_{k=0..n+1} (4/(8k+1)-2/(8k+4)-1/(8k+5)-1/(8k+6))/16^k).
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0
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4, 51, 805, 12868, 205888, 3294199, 52707179, 843314857, 13493037705, 215888603273, 3454217652358, 55267482437723, 884279719003556, 14148475504056881, 226375608064910089, 3622009729038561422, 57952155664616982740, 927234490633871723826, 14835751850141947581204
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OFFSET
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0,1
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COMMENTS
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The formula gives an approximation to 16^n*Pi. The first 300 terms agree with ceiling(16^n*Pi) but this may not be true in general.
Terms in base 16 are 4, 33, 325, 3244, 32440, 3243F7, 3243F6B, 3243F6A9, 3243F6A89, 3243F6A889, 3243F6A8886, 3243F6A8885B, 3243F6A8885A4, 3243F6A8885A31, 3243F6A8885A309, 3243F6A8885A308E, 3243F6A8885A308D4, 3243F6A8885A308D32, 3243F6A8885A308D314, 3243F6A8885A308D3132, ...
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LINKS
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FORMULA
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a(n) = ceiling((16^n)*Sum_{k=0..n+1} (4/(8k+1)-2/(8k+4)-1/(8k+5)-1/(8k+6))/16^k).
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MATHEMATICA
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Array[Ceiling[(16^#)*Sum[(4/(8 k + 1) - 2/(8 k + 4) - 1/(8 k + 5) - 1/(8 k + 6))/16^k, {k, 0, # + 1}]] &, 19, 0] (* Michael De Vlieger, May 01 2021 *)
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PROG
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(PARI) a(n) = ceil((16^n)*sum(k=0, n+1, (4/(8*k+1)-2/(8*k+4)-1/(8*k+5)-1/(8*k+6))/16^k)); \\ Michel Marcus, Apr 23 2021
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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