

A343269


a(n) is the smallest integer whose orbit length is n under iteration of the map r > A061602(r).


0



1, 0, 169, 78, 69, 26, 24, 4, 22, 5, 122, 25, 14, 127, 6, 3, 12, 33, 136, 256, 57, 247, 148, 38, 1478, 368, 79, 1458, 48, 44, 29, 7, 13, 34, 9, 8, 23, 234, 37, 337, 58, 46, 139, 138, 369, 239, 267, 36, 334, 289, 3555, 49, 144, 45, 229, 2569, 22888, 136789, 334479, 1479, 1233466
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OFFSET

1,3


COMMENTS

A303935 provides the orbit's lengths, i.e., the number of needed steps, starting from a given number, to reach a value that already exists in trajectory.
This sequence is infinite. Actually, given a number x whose orbit's length is k, one can always build a number y whose orbit's length is (k+1).
For instance, just consider either the number 10^(x1), or Rx (the repunit of length x), or any other xdigit binary string, all of them leading to the number x after application of the mapping function: A061602(y) = x.
Indeed, none of them will correspond to the smallest integer m such that A303935(m) = k + 1.
In fact, it becomes computationally hard to determine further terms since, as in the Collatz mapping function and other similar problems, there is no predictable way to define the exact complete path without calculating all intermediary orbit's components until one reaches a previously calculated or encountered number.
a(59) = 334479, a(60) = 1479, a(61) = 1233466, next terms = ?


LINKS



EXAMPLE

a(6) = 26 because A303935(26) = 6, and 26 is the smallest nonnegative integer m such that A303935(m) = 6.


CROSSREFS



KEYWORD

nonn,base


AUTHOR



STATUS

approved



