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A343269 a(n) is the smallest integer whose orbit length is n under iteration of the map r -> A061602(r). 0

%I #23 Apr 13 2021 18:33:05

%S 1,0,169,78,69,26,24,4,22,5,122,25,14,127,6,3,12,33,136,256,57,247,

%T 148,38,1478,368,79,1458,48,44,29,7,13,34,9,8,23,234,37,337,58,46,139,

%U 138,369,239,267,36,334,289,3555,49,144,45,229,2569,22888,136789,334479,1479,1233466

%N a(n) is the smallest integer whose orbit length is n under iteration of the map r -> A061602(r).

%C A303935 provides the orbit's lengths, i.e., the number of needed steps, starting from a given number, to reach a value that already exists in trajectory.

%C This sequence is infinite. Actually, given a number x whose orbit's length is k, one can always build a number y whose orbit's length is (k+1).

%C For instance, just consider either the number 10^(x-1), or Rx (the repunit of length x), or any other x-digit binary string, all of them leading to the number x after application of the mapping function: A061602(y) = x.

%C Indeed, none of them will correspond to the smallest integer m such that A303935(m) = k + 1.

%C In fact, it becomes computationally hard to determine further terms since, as in the Collatz mapping function and other similar problems, there is no predictable way to define the exact complete path without calculating all intermediary orbit's components until one reaches a previously calculated or encountered number.

%C a(59) = 334479, a(60) = 1479, a(61) = 1233466, next terms = ?

%e a(6) = 26 because A303935(26) = 6, and 26 is the smallest nonnegative integer m such that A303935(m) = 6.

%Y Cf. A303935 (orbit's length), A061602 (sum of factorials of digits), A014080 (factorions).

%Y Cf. A193163, A214285, A254499, A188283, A244090.

%K nonn,base

%O 1,3

%A _Lamine Ngom_, Apr 10 2021

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Last modified April 27 04:00 EDT 2024. Contains 372009 sequences. (Running on oeis4.)