

A343022


Discriminants with exactly 1 associated cyclic cubic field.


8



49, 81, 169, 361, 961, 1369, 1849, 3721, 4489, 5329, 6241, 9409, 10609, 11881, 16129, 19321, 22801, 24649, 26569, 32761, 37249, 39601, 44521, 49729, 52441, 58081, 73441, 76729, 80089, 94249, 97969, 109561, 113569, 121801, 134689, 139129, 143641, 157609, 167281, 177241
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OFFSET

1,1


COMMENTS

A cubic field is cyclic if and only if its discriminant is a square. Hence all terms are squares.
Numbers of the form k^2 where A160498(k) = 2.
Numbers of the form k^2 where k is in A002476 U {9}. That is to say, numbers of the form k^2 where k = 9 or is a prime congruent to 1 modulo 3.
In general, there are exactly 2^(t1) (cyclic) cubic fields with discriminant k^2 if and only if k is of the form (p_1)*(p_2)*...*(p_t) or 9*(p_1)*(p_2)*...*(p_{t1}) with distinct primes p_i == 1 (mod 3), See A343000 for more detailed information.


LINKS



FORMULA



EXAMPLE

169 is a term since the one (and only one) cyclic cubic field with that discriminant is Q[x]/(x^3  x^2  4x  1).


PROG

(PARI) isA343022(n) = if(issquare(n), my(k=sqrtint(n)); k==9  (isprime(k) && k%3==1), 0)


CROSSREFS

Discriminants and their square roots of cyclic cubic fields:
Exactly 1 associated cyclic cubic field: this sequence, A002476 U {9}.


KEYWORD

nonn,easy


AUTHOR



STATUS

approved



