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A342031
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Starts of runs of 5 consecutive numbers that have mutually distinct exponents in their prime factorization (A130091).
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6
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1, 16, 241, 2644, 4372, 1431124, 12502348, 112753348, 750031648, 2844282247, 5882272324, 6741230497, 8004453748, 87346072024, 130489991521, 218551872247, 245127093748, 460925878624, 804065433748, 1176638279524, 2210511903748, 2404792968748, 2483167488748, 3121595927521
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OFFSET
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1,2
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COMMENTS
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Bernardo Recamán Santos (2015) showed that there is no run of more than 23 consecutive numbers, since numbers of the form 36*k - 6 and 36*k + 6 do not have distinct exponents. Pace Nielsen and Adam P. Goucher showed that there can be only finitely many runs of 23 consecutive numbers (see MathOverflow link).
Aktaş and Ram Murty (2017) gave an explicit upper bound to such a run of 23 numbers. They found the first 5 terms of this sequence (and stated that there are a few more known up to 7*10^8), and said that we may conjecture (based on numerical evidence) that there are no 6 consecutive numbers.
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LINKS
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EXAMPLE
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16 is a term since 16 = 2^4, 17, 18 = 2*3^2, 19 and 20 = 2^2*5 all have distinct exponents in their prime factorization.
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MATHEMATICA
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q[n_] := Length[(e = FactorInteger[n][[;; , 2]])] == Length[Union[e]]; v = q /@ Range[5]; seq = {}; Do[If[And @@ v, AppendTo[seq, k - 5]]; v = Join[Rest[v], {q[k]}], {k, 6, 1.3*10^6}]; seq
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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