OFFSET
1,2
COMMENTS
In order to get the maximum number, the ratio of the two resistances should be a transcendental number.
It appears that the resistance values always come in pairs, but this has not been proven. (This sequence only enumerates half). In particular, it seems that switching the two types of resistor and exchanging parallel with serial will always give a different value. Neither of these on its own is sufficient.
LINKS
EXAMPLE
In the following let x and y be the values of the two resistors.
With 1 component the resistances are {x, y}, so a(1) = 2/2 = 1.
With 2 components the resistances are {2*x, x/2, 2*y, y/2, x + y, x*y/(x + y)}, so a(2) = 6/2 = 3.
PROG
(PARI)
ParSer(u, v)={concat(concat(vector(#u, i, vector(#v, j, u[i]+v[j]))), concat(vector(#u, i, vector(#v, j, 1/(1/u[i]+1/v[j])))))}
S(n)={my(v=vector(n)); v[1]=[1, 'x]; for(n=2, #v, v[n]=Set(concat(vector(n\2, k, ParSer(v[k], v[n-k]))))); v}
a(n)={#(S(n)[n])/2}
CROSSREFS
KEYWORD
nonn,more
AUTHOR
Andrew Howroyd, Nov 08 2020
EXTENSIONS
a(11) from Alois P. Heinz, Dec 21 2020
a(12)-a(13) from David Einstein, Feb 23 2022
STATUS
approved