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 A338763 Let L_1 = (1, 2, ...); for any n > 0, let M_n = Min_{k > 0} L_n(k) + L_n(k+1) and K_n = Min_{ k | L_n(k) + L_n(k+1) = M_n }, L_{n+1} is obtained by replacing the two terms L_n(K_n) and L_n(K_n+1) by M_n in L_n; a(n) = M_n. 2
 3, 6, 9, 13, 15, 17, 21, 25, 28, 29, 33, 37, 38, 41, 45, 49, 53, 54, 57, 61, 65, 66, 69, 70, 73, 77, 81, 85, 86, 89, 93, 97, 101, 102, 105, 109, 113, 117, 118, 120, 121, 125, 129, 133, 134, 137, 141, 145, 149, 150, 153, 156, 157, 161, 165, 166, 169, 173, 177 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS In other words, we start with the natural numbers and repeatedly replace the leftmost pair of consecutive terms with minimal sum by its sum; a(n) corresponds to the sum at n-th step. This sequence is weakly increasing, and tends to infinity (as for any m > 0, there are only finitely many runs of two or more consecutive integers with a sum < m). LINKS Rémy Sigrist, Table of n, a(n) for n = 1..10000 Rémy Sigrist, PARI program for A338763 FORMULA a(n) <= a(n+1). EXAMPLE The first terms, alongside L_n, are: n a(n) L_n -- ---- ---------------------------------------------------------- 1 3 { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, ... } 2 6 { 3, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, ... } 3 9 { 6, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, ... } 4 13 { 6, 9, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, ... } 5 15 { 6, 9, 13, 8, 9, 10, 11, 12, 13, 14, 15, ... } 6 17 { 15, 13, 8, 9, 10, 11, 12, 13, 14, 15, ... } 7 21 { 15, 13, 17, 10, 11, 12, 13, 14, 15, ... } 8 25 { 15, 13, 17, 21, 12, 13, 14, 15, ... } 9 28 { 15, 13, 17, 21, 25, 14, 15, ... } 10 29 { 28, 17, 21, 25, 14, 15, ... } PROG (PARI) See Links section. CROSSREFS Cf. A326936, A338764. Sequence in context: A061514 A078559 A317557 * A159908 A236761 A088364 Adjacent sequences: A338760 A338761 A338762 * A338764 A338765 A338766 KEYWORD nonn AUTHOR Rémy Sigrist, Nov 07 2020 STATUS approved

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Last modified April 14 09:38 EDT 2024. Contains 371657 sequences. (Running on oeis4.)