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 A334194 a(n) = n - d1*d2, where d1, d2 are the distances from n to the previous and the next prime number respectively. 0
 0, 0, 1, 3, 1, 5, -1, 5, 5, 7, 3, 11, 5, 11, 11, 13, 9, 17, 11, 17, 17, 19, -1, 19, 17, 17, 19, 23, 17, 29, 19, 27, 25, 25, 27, 31, 13, 35, 35, 37, 33, 41, 35, 41, 41, 43, 23, 43, 41, 41, 43, 47, 17, 49, 47, 47, 49, 53, 47, 59, 49, 57, 55 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,4 COMMENTS Except of a(1), a(2), a(7) and a(23) that are negative or zero, it seems that the density of the prime numbers is such that; n is greater than the product d1 * d2 for each n. So I conjecture that n >  d1 * d2 for every N - {1, 2, 7, 23}. If it is true, means that there is at least 1 prime number in space [n - sqrt(n), n + sqrt(n)]. I also conjecture that lim_{n -> oo} (n - d1*d2)/n = a(n)/n = 1. LINKS EXAMPLE For n = 9, a(9) = 9 - (9 - 7) * (11 - 9) = 9 - 2 * 2 = 5, because the previous prime is 7 and the next prime is 11. For n = 23, the previous prime is 19 so d1 = 23 - 19 = 4. The next prime is 29 so d2 = 29 - 23 = 6. The product d1 * d2 = 4 * 6 = 24 (maybe the last time that the product d1 * d2 > n). So a(23) = 23 - 24 = -1. PROG (PARI) for(n = 1, 100, d1 = n - precprime(n - 1); d2 = nextprime(n + 1) - n; print1(n - d1*d2", ")) CROSSREFS Cf. A000040, A151799, A151800. Sequence in context: A114567 A001051 A214737 * A046730 A002972 A324896 Adjacent sequences:  A334191 A334192 A334193 * A334195 A334196 A334197 KEYWORD sign AUTHOR Dimitris Valianatos, Apr 18 2020 STATUS approved

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Last modified May 10 01:36 EDT 2021. Contains 343747 sequences. (Running on oeis4.)