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A329923
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Beatty sequence for (2+sqrt(34))/5.
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3
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1, 3, 4, 6, 7, 9, 10, 12, 14, 15, 17, 18, 20, 21, 23, 25, 26, 28, 29, 31, 32, 34, 36, 37, 39, 40, 42, 43, 45, 46, 48, 50, 51, 53, 54, 56, 57, 59, 61, 62, 64, 65, 67, 68, 70, 72, 73, 75, 76, 78, 79, 81, 83, 84, 86, 87, 89, 90, 92, 93, 95, 97, 98, 100, 101
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OFFSET
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1,2
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COMMENTS
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Let r = (2+sqrt(34))/5. Then (floor(n*r)) and (floor(n*r + 6r/5)) are a pair of Beatty sequences; i.e., every positive integer is in exactly one of the sequences. See the Guide to related sequences at A329825.
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LINKS
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FORMULA
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a(n) = floor(n*r), where r = (2+sqrt(34))/5.
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MATHEMATICA
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t = 6/5; r = Simplify[(2 - t + Sqrt[t^2 + 4])/2]; s = Simplify[r/(r - 1)];
Table[Floor[r*n], {n, 1, 200}] (* A329923 *)
Table[Floor[s*n], {n, 1, 200}] (* A329924 *)
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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