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A329924
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Beatty sequence for (8+sqrt(34))/5.
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3
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2, 5, 8, 11, 13, 16, 19, 22, 24, 27, 30, 33, 35, 38, 41, 44, 47, 49, 52, 55, 58, 60, 63, 66, 69, 71, 74, 77, 80, 82, 85, 88, 91, 94, 96, 99, 102, 105, 107, 110, 113, 116, 118, 121, 124, 127, 130, 132, 135, 138, 141, 143, 146, 149, 152, 154, 157, 160, 163
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OFFSET
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1,1
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COMMENTS
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Let r = (2+sqrt(34))/5. Then (floor(n*r)) and (floor(n*r + 6r/5)) are a pair of Beatty sequences; i.e., every positive integer is in exactly one of the sequences. See the Guide to related sequences at A329825.
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LINKS
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FORMULA
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a(n) = floor(n*s), where s = (8+sqrt(34))/5.
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MATHEMATICA
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t = 6/5; r = Simplify[(2 - t + Sqrt[t^2 + 4])/2]; s = Simplify[r/(r - 1)];
Table[Floor[r*n], {n, 1, 200}] (* A329923 *)
Table[Floor[s*n], {n, 1, 200}] (* A329924 *)
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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