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 A322583 a(n) is the number of factorizations of n into factorial numbers larger than one; a(1) = 1. 8
 1, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,24 COMMENTS Values 1..7 occur for the first time at n = 1, 24, 576, 13824, 69120, 414720, 1658880. In range 1..69120 differs from A034876 only at positions n = 1, 2, 9, 10 and 16. LINKS Antti Karttunen, Table of n, a(n) for n = 1..69120 FORMULA a(24^n) = a(A009968(n)) = n+1. EXAMPLE a(4) = 1 because 4 = 2! * 2!. a(24) = 2 because 24 = 4! = 3! * 2! * 2!. a(576) = 3 because 576 = 4! * 4! = 4! * 3! * 2! * 2! = (3!)^2 * (2!)^4. a(13824) = 4 because 13824 = (4!)^3 = (4!)^2 * 3! * (2!)^2 = 4! * (3!)^2 * (2!)^4 = (3!)^3 * (2!)^6. a(69120) = 5 because 69120 = 6! * 4! * 2! * 2! = 6! * 3! * 2! * 2! * 2! * 2! = 5! * 3! * 3! * 2! * 2! * 2! * 2! = 5! * 4! * 4! = 5! * 4! * 3! * 2! * 2!. Note that 69120 < 24^4 = 331776. PROG (PARI) A322583(n, m=n) = if(1==n, 1, my(s=0); for(i=2, oo, my(f=i!); if(f>m, return(s)); if(!(n%f), s += A322583(n/f, f)))); (PARI) A034968(n) = { my(s=0, b=2, d); while(n, d = (n%b); s += d; n = (n-d)/b; b++); (s); }; A322583(n, m=n) = if(1==n, 1, my(s=0); fordiv(n, d, if((d>1)&&(d<=m)&&(1==A034968(d)), s += A322583(n/d, d))); (s)); CROSSREFS Cf. A000142, A001013 (positions of nonzero terms), A009968, A034876, A034968. Sequence in context: A086078 A323913 A014082 * A102354 A157228 A193138 Adjacent sequences:  A322580 A322581 A322582 * A322584 A322585 A322586 KEYWORD nonn AUTHOR Antti Karttunen, Dec 25 2018 STATUS approved

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Last modified August 25 14:29 EDT 2019. Contains 326324 sequences. (Running on oeis4.)