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A320626 a(n) = (A006134(prime(n)-1) - Legendre(prime(n), 3))/prime(n)^2. 1
1, 1, 4, 26, 2074, 21660, 2804068, 33847970, 5345496688, 12201269878660, 165029257057602, 433037204976615540, 85637003420093445994, 1215603499085916654728, 248871244937134915010626, 753881874165723132009014662, 2359161060012378685209851991166 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,3

COMMENTS

a(n) is always an integer.

Are there any primes p such that p^3 divides A006134(p-1) - Legendre(p, 3)?

LINKS

Table of n, a(n) for n=1..17.

EXAMPLE

a(1) = (binomial(0, 0) + binomial(2, 1) + 1)/4 = 4/4 = 1.

a(2) = (binomial(0, 0) + binomial(2, 1) + binomial(4, 2))/9 = 9/9 = 1.

a(3) = (binomial(0, 0) + binomial(2, 1) + binomial(4, 2) + binomial(6, 3) + binomial(8, 4) + 1)/25 = 100/25 = 4.

PROG

(PARI) A006134(n) = sum(k=0, n, binomial(2*k, k))

a(n) = my(p=prime(n)); (A006134(p-1) - kronecker(p, 3))/p^2

CROSSREFS

Cf. A006134, A102283, A320624.

Sequence in context: A322395 A326264 A132488 * A144990 A102199 A125723

Adjacent sequences:  A320623 A320624 A320625 * A320627 A320628 A320629

KEYWORD

nonn

AUTHOR

Jianing Song, Oct 18 2018

STATUS

approved

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Last modified September 18 09:56 EDT 2019. Contains 327169 sequences. (Running on oeis4.)