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A319848
Irregular triangle read by rows in which row n lists the even divisors of n in decreasing order together with the odd divisors of n in decreasing order.
7
1, 2, 1, 3, 1, 4, 2, 1, 5, 1, 6, 2, 3, 1, 7, 1, 8, 4, 2, 1, 9, 3, 1, 10, 2, 5, 1, 11, 1, 12, 6, 4, 2, 3, 1, 13, 1, 14, 2, 7, 1, 15, 5, 3, 1, 16, 8, 4, 2, 1, 17, 1, 18, 6, 2, 9, 3, 1, 19, 1, 20, 10, 4, 2, 5, 1, 21, 7, 3, 1, 22, 2, 11, 1, 23, 1, 24, 12, 8, 6, 4, 2, 3, 1, 25, 5, 1, 26, 2, 13, 1, 27, 9, 3, 1
OFFSET
1,2
COMMENTS
Consider the diagram with overlapping periodic curves that appears in the Links section (figure 1). The number of curves that contain the point [n,0] equals the number of divisors of n. The simpler interpretation of the diagram is that the curve of diameter d represents the divisor d of n. Now here we introduce a new interpretation: the curve of diameter d that contains the point [n,0] represents the divisor c of n, where c = n/d. This model has the property that each odd quadrant centered at [n,0] contains the curves that represent the even divisors of n, and each even quadrant centered at [n,0] contains the curves that represent the odd divisors of n.
We can find the n-th row of the triangle as follows:
Consider only the semicircumferences that contain the point [n,0].
If n is an even number, in the first quadrant from bottom to top we can see the curves that represent the even divisors of n in decreasing order. Also we can see these curves in the third quadrant from top to bottom.
Then, in the second quadrant from bottom to top we can see the curves that represent the odd divisors of n in decreasing order. Also we can see these curves in the fourth quadrant from top to bottom (see example).
Sequences of the same family are shown below:
-----------------------------------
Triangle Order of divisors of n
-----------------------------------
A299481 odd v t.w. even ^
A299483 odd ^ t.w. even v
A319844 even v t.w. odd ^
A319845 even ^ t.w. odd v
A319846 odd v t.w. even v
A319847 odd ^ t.w. even ^
This seq. even v t.w. odd v
A319849 even ^ t.w. odd ^
-----------------------------------
In the above table we have that:
"even v" means "even divisors of n in decreasing order".
"even ^" means "even divisors of n in increasing order".
"odd v" means "odd divisors of n in decreasing order".
"odd ^" means "odd divisors of n in increasing order".
"t.w." means "together with".
EXAMPLE
Triangle begins:
1;
2, 1;
3, 1;
4, 2, 1;
5, 1;
6, 2, 3, 1;
7, 1;
8, 4, 2, 1;
9, 3, 1;
10, 2, 5, 1;
11, 1;
12, 6, 4, 2, 3, 1;
13, 1;
14, 2, 7, 1;
15, 5, 3, 1;
16, 8, 4, 2, 1;
17, 1;
18, 6, 2, 9, 3, 1;
19, 1;
20, 10, 4, 2, 5, 1;
21, 7, 3, 1;
22, 2, 11, 1;
23, 1;
24, 12, 8, 6, 4, 2, 3, 1;
25, 5, 1;
26, 2, 13, 1;
27, 9, 3, 1;
28, 14, 4, 2, 7, 1;
...
For n = 12 the divisors of 12 are [1, 2, 3, 4, 6, 12]. The even divisors of 12 in decreasing order are [12, 6, 4, 2], and the odd divisors of 12 in decreasing order are [3, 1], so the 12th row of triangle is [12, 6, 4, 2, 3, 1].
On the other hand, consider the diagram that appears in the Links section (figure 1). Then consider only the semicircumferences that contain the point [12,0]. In the first quadrant, from bottom to top, we can see the curves with diameters [1, 2, 3, 6]. Also we can see these curves in the third quadrant from top to bottom. The associated numbers c = 12/d are [12, 6, 4, 2] respectively. These are the even divisors of n in decreasing order. Then, in the second quadrant, from bottom to top, we can see the curves with diameters [4, 12]. Also we can see these curves in the fourth quadrant from top to bottom. The associated numbers c = 12/d are [3, 1] respectively. These are the odd divisors of 12 in decreasing order. Finally all numbers c obtained are [12, 6, 4, 2, 3, 1] equaling the 12th row of triangle.
From David A. Corneth, Jan 17 2019: (Start)
For n = 100, we have n even so first even divisors in decreasing order and then odd divisors in decreasing order. The even divisors of 100 are twice the divisors of 100/2 = 50. Those divisors, in decreasing order, are: 100, 50, 20, 10, 4, 2.
The odd divisors of 100 in decreasing order are the odd divisors of the odd part of 100, which is 25. Those divisors are 25, 5, 1.
Concatenating all these divisors gives: 100, 50, 20, 10, 4, 2, 25, 5, 1. (End)
PROG
(PARI) row(n) = my(d=divisors(n)); concat(Vecrev(select(x->!(x%2), d)), Vecrev(select(x->(x%2), d)));
lista(nn) = {for (n=1, nn, my(r = row(n)); for (k=1, #r, print1(r[k], ", ")); ); } \\ Michel Marcus, Jan 17 2019
(PARI) row(n) = if(n%2==0, concat(Vecrev(divisors(n >> 1)) << 1, Vecrev(divisors(n >> valuation(n, 2)))), Vecrev(divisors(n))) \\ David A. Corneth, Jan 17 2019
CROSSREFS
Row sums give A000203.
Row n has length A000005(n).
Column 1 gives A000027.
Right border gives A000012.
Sequence in context: A299483 A113398 A210959 * A364749 A233772 A056538
KEYWORD
nonn,tabf
AUTHOR
Omar E. Pol, Sep 29 2018
STATUS
approved