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A299485
List of pairs (a,b) where in the n-th pair, a = number of even divisors of n and b = number of odd divisors of n.
9
0, 1, 1, 1, 0, 2, 2, 1, 0, 2, 2, 2, 0, 2, 3, 1, 0, 3, 2, 2, 0, 2, 4, 2, 0, 2, 2, 2, 0, 4, 4, 1, 0, 2, 3, 3, 0, 2, 4, 2, 0, 4, 2, 2, 0, 2, 6, 2, 0, 3, 2, 2, 0, 4, 4, 2, 0, 2, 4, 4, 0, 2, 5, 1, 0, 4, 2, 2, 0, 4, 6, 3, 0, 2, 2, 2, 0, 4, 6, 2, 0, 2, 4, 4, 0, 2, 4, 2, 0, 6, 2, 2, 0, 2, 8, 2, 0, 3, 3, 3, 0, 4, 4, 2
OFFSET
1,6
COMMENTS
Also sequence found by reading in the lower part of the diagram of periodic curves for the number of divisors of n (see the first diagram in the Links section). Explanation: the number of curves that emerge from the point (n, 0) to the left hand in the lower part of the diagram equals A183063(n) the number of even divisors of n. The number of curves that emerge from the same point (n, 0) to the right hand in the lower part of the diagram equals A001227(n) the number of odd divisors of n. So the n-th pair is (A183063(n), A001227(n)). Also the total number of curves that emerges from the same point (n, 0) equals A000005(n), the number of divisors of n. Note that at the point (n, 0) the inflection point of the curve that emerges with diameter k represents the divisor n/k.
The second diagram in the links section shows only the lower part from the first diagram, upside down.
FORMULA
Pair(a,b) = Pair(A183063(n), A001227(n)).
EXAMPLE
Array begins:
1 0 1
2 1 1
3 0 2
4 2 1
5 0 2
6 2 2
7 0 2
8 3 1
9 0 3
10 2 2
11 0 2
12 4 2
...
MATHEMATICA
Array[{#2, #1 - #2} & @@ {DivisorSigma[0, #], DivisorSum[#, 1 &, EvenQ]} &, 52] // Flatten (* Michael De Vlieger, Mar 04 2018 *)
CROSSREFS
Another version of A299480.
Row sums give A000005.
Sequence in context: A287200 A284387 A143667 * A246785 A084934 A125927
KEYWORD
nonn,tabf
AUTHOR
Omar E. Pol, Mar 03 2018
STATUS
approved