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A317095 a(n) = 40*n. 0
0, 40, 80, 120, 160, 200, 240, 280, 320, 360, 400, 440, 480, 520, 560, 600, 640, 680, 720, 760, 800, 840, 880, 920, 960, 1000, 1040, 1080, 1120, 1160, 1200, 1240, 1280, 1320, 1360, 1400, 1440, 1480, 1520, 1560, 1600, 1640, 1680, 1720, 1760, 1800, 1840, 1880 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
a(n) is equal to the freshwater zone below sea level for a water table of elevation n above sea level in a simplified freshwater-saltwater interface in a coastal water-table aquifer (cf. Barlow, 2003, p. 14, eq. (2) and p. 15, Fig. B-1 and B-2).
From Bruno Berselli, Sep 10 2018: (Start)
After 0, subsequence of A065607: 1/a(n)^2 + 1/(30*n)^2 = 1/(24*n)^2, with n > 0 and a(n) > 30*n.
Also, all positive terms belong to A049094: 2^(40*n)-1 = 1024^(4*n)-1 and (25*41-1)^(4*n)-1 is divisible by 25. (End)
LINKS
Wikipedia, Aquifer
FORMULA
O.g.f.: 40*x/(1 - x)^2.
E.g.f.: 40*x*exp(x). - Bruno Berselli, Sep 10 2018
a(n) = 2*a(n - 1) - a(n - 2) for n > 1. - Stefano Spezia, Sep 07 2018
a(n) = A008586(A008592(n)) = 4*A008592(n).
a(n) = A010692(n)*A008586(n) = 10*A008586(n).
a(n) = A008602(A005843(n)) = 20*A005843(n).
a(n) = A007395(n)*A008602(n) = 2*A008602(n).
MATHEMATICA
Table[40 n, {n, 0, 50}] (* or *)
LinearRecurrence[{2, -1}, {0, 40}, 50] (* or *)
CoefficientList[Series[40*x/(1 - x)^2, {x, 0, 50}], x] (* Stefano Spezia, Sep 07 2018 *)
PROG
(PARI) a(n) = 40*n
(PARI) a(n) = if(n==0, 0, if(n==1, 40, 2*a(n-1)-a(n-2)))
(PARI) concat(0, Vec(40*x/(1-x)^2 + O(x^60)))
CROSSREFS
Row n = 40 of A004247. Intersection of A008587 and A008590.
After 0, subsequence of A005101.
Sequence in context: A253692 A253699 A037975 * A039468 A181458 A069070
KEYWORD
nonn,easy
AUTHOR
Felix Fröhlich, Sep 07 2018
STATUS
approved

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Last modified April 16 02:41 EDT 2024. Contains 371696 sequences. (Running on oeis4.)