A309493 Highly Brazilian numbers (A329383) that are not highly composite numbers (A002182).

7, 15, 40, 336, 1440, 5405400

Offset

1,1

Comments

Is this sequence finite or infinite?

Indeed, from 6486480 to 321253732800, that is, during 41 successive terms (maybe more?), highly Brazilian numbers are the same as highly composite numbers.

The data for this sequence comes from the new terms in the b-file of A066044 found by Giovanni Resta.

Why are these six numbers HB (highly Brazilian) and not HC (highly composite)? (See link Why HB and not HC? for more details)

1) For 7, 15 and 40, it is because they have a Brazilian representation with 3 or 4 digits and belong to A326380 (see examples).

2) For 336, 1440 and 5405400, it is because each of these three terms HB r is non-oblong, belong to A326386 and the greatest HC m less than r is oblong with the same number of divisors.

a(7) > A329383(91) = 321253732800.

Links

Table of n, a(n) for n=1..6.

Bernard Schott, Why HB and not HC?

Example

a(1) = 7 because 7 is the smallest Brazilian number with 7 = 111_2 so beta(7) = 1, as tau(7) = tau(2) = 2, 7 is highly Brazilian but cannot be highly composite.
a(2) = 15 because 15 is the smallest integer 2-Brazilian with 15 = 1111_2 = 33_4 and beta(15) = 2, as tau(15) = tau(6) = 4, 15 is highly Brazilian but not highly composite.
a(3) = 40 because 40 is the smallest integer 4-Brazilian with 40 = 1111_3 = 55_7 = 44_9 = 22_19 so beta(40) = 4, as tau(40) = tau(24) = 8, 40 is highly Brazilian but not highly composite.
a(4) = 336 because beta(336) = 9 and tau(336) = tau(240) = 20.
a(5) = 1440 because beta(1440) = 17 and tau(1440) = tau(1260) = 36.
a(6) = 5405400 because beta(5405400) = 191 and tau(5405400) = tau(4324320) = 384.

Crossrefs

Cf. A002182, A279930, A309039, A329383.

Sequence in context: A041094 A042287 A309732 * A145978 A037376 A141548

Adjacent sequences: A309490 A309491 A309492 * A309494 A309495 A309496

Keyword

nonn,base,more

Author

Bernard Schott, Aug 04 2019

Status

approved