OFFSET
0,2
FORMULA
a(n) = (n+1)^(4*n)/(n+1)! - Sum_{k=1..n} (n+1)^(4*k-4)/k! * (n-k+1)^4 * a(n-k) for n>0 with a(0)=1.
From Seiichi Manyama, Mar 24 2026: (Start)
1/(n+1)! = Sum_{k=0..n} ((k+1)/(n+1)^(k+1))^4 * a(k)/(n-k)!.
G.f. A(x) satisfies [x^n] exp(n^4*x) (1 - E^4(x*A(x))) = 0 for n > 0, where E is the Euler operator x*d/dx. (End)
PROG
CROSSREFS
KEYWORD
nonn
AUTHOR
Paul D. Hanna, May 12 2018
STATUS
approved
