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A302706
a(n) is the maximum remainder of x^2 + y^2 divided by x + y with 0 < x <= y <= n.
1
0, 2, 3, 4, 5, 6, 10, 11, 12, 13, 14, 16, 18, 18, 18, 26, 27, 28, 29, 30, 32, 32, 33, 34, 35, 40, 40, 40, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 72, 72, 72, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 98, 98, 98, 98, 98, 98, 99, 100, 104, 104, 122, 123, 124, 125, 126, 127, 128, 129, 130, 131, 132
OFFSET
1,2
COMMENTS
Values of a(n) such that a(n) is prime are 2, 3, 5, 11, 13, 29, 53, 59, 61, 83, 89, 127, 131, 137, 139, 173, ...
Conjecture: lim_{n->inf} a(n)/(2n) = 1, with both variables x and y taking values asymptotically close to n. - Andres Cicuttin, Oct 18 2018
EXAMPLE
a(1) = 0 because x = y = 1 is only option.
a(13) = a(14) = a(15) = 18 because (7^2 + 13^2) mod (7 + 13) = 18 is the largest corresponding remainder for them.
MATHEMATICA
a[n_]:=Table[Table[Mod[x^2+y^2 , x+y], {x, 1, y}], {y, 1, n}]//Flatten//Max;
Table[a[n], {n, 1, 100}]
PROG
(PARI) a(n) = vecmax(vector(n, x, vecmax(vector(x, y, (x^2+y^2) % (x+y))))); \\ after Michel Marcus at A302245
CROSSREFS
Sequence in context: A037476 A007093 A285469 * A047423 A032970 A137691
KEYWORD
nonn,easy
AUTHOR
Altug Alkan and Andres Cicuttin, Apr 12 2018
STATUS
approved