OFFSET
1,1
COMMENTS
The sequence starts with a(1) = 9 and is always extended with the smallest integer not yet present in the sequence and not leading to a contradiction.
LINKS
Jean-Marc Falcoz, Table of n, a(n) for n = 1..300
FORMULA
a(n) = c(n) - c(n-1), where c(n) = concatenation of the first n digits; c(n) ~ 0.99*10^n, a(n) ~ 0.89*10^n. See A300000 for the proof. - M. F. Hasler, Feb 22 2018
EXAMPLE
9 + 90 = 99 which is the concatenation of 9 and 9.
9 + 90 + 891 = 990 which is the concatenation of 9, 9 and 0.
9 + 90 + 891 + 8918 = 9908 which is the concatenation of 9, 9, 0 and 8.
From n = 3 on, a(n) can be computed directly as c(n) - c(n-1), cf. formula: a(3) = 990 - 99 = 891, a(4) = 9908 - 990 = 8918, etc. - M. F. Hasler, Feb 22 2018
PROG
(PARI) a(n, show=1, a=9, c=a, d=[a])={for(n=2, n, show&&print1(a", "); a=-c+c=c*10+d[1]; d=concat(d[^1], if(n>2, digits(a)))); a} \\ M. F. Hasler, Feb 22 2018
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Eric Angelini and Jean-Marc Falcoz, Feb 21 2018
STATUS
approved