1,2

Table of n, a(n) for n=1..5.

Robert Israel, 51 terms of the sequence (it is possible that this list is missing some terms, so it is not a b-file)

1365 = 3*5*7*13 is a term because d(1365) = 2^4 and 2^16 == 16 (mod 3*5*7*13).

(PARI) isok(n) = (n%2==1) && (dn=numdiv(n)) && (Mod(2, n)^dn == dn); \\ Michel Marcus, Feb 25 2019

Cf. A000005.

Sequence in context: A022204 A015405 A295466 * A180089 A020409 A231268

Adjacent sequences: A292777 A292778 A292779 * A292781 A292782 A292783

nonn,more

Altug Alkan, Sep 23 2017

approved