|
|
A290870
|
|
a(n) is the number of ways to represent n as n = x*y + y*z + z*x where 0 < x < y < z.
|
|
1
|
|
|
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 1, 1, 0, 0, 2, 0, 0, 2, 1, 0, 2, 0, 2, 1, 0, 1, 2, 1, 0, 2, 2, 0, 3, 0, 1, 3, 0, 1, 4, 0, 1, 2, 2, 1, 2, 2, 2, 3, 0, 0, 5, 0, 2, 3, 2, 1, 2, 2, 1, 4, 2, 0, 6, 0, 1, 4, 2, 3, 2, 0, 4, 3, 2, 1, 5, 2, 0, 4, 4, 0, 5, 2, 2, 4, 0, 3, 6, 2, 1, 3, 3, 1
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,23
|
|
COMMENTS
|
a(n) = 0 if and only if n is a term of A000926.
a(n) = 1 if and only if n is a term of A093669.
|
|
LINKS
|
|
|
FORMULA
|
For the triples (x,y,z) we have x < sqrt(n / 3), y < (n - x^2) / (2 * x), z = (n - x*y) / (x + y) which must be integer. - David A. Corneth, Oct 01 2017
|
|
EXAMPLE
|
For (x, y, z) = (1, 3, 5), we have x * y + y * z + z * x = 1 * 3 + 3 * 5 + 5 * 1 = 23 and similarily for (x, y, z) = (1, 2, 7), we have x * y + y * z + z * x = 23. Those 2 triples are all for n=23, so a(23) = 2. - David A. Corneth, Oct 01 2017
|
|
PROG
|
(PARI) N=10^3; V=vector(N);
{ for (x=1, N,
for (y=x+1, N, t=x*y; if( t > N, break() );
for (z=y+1, N,
tt = t + y*z + z*x; if( tt > N, break() );
V[tt]+=1;
); ); ); }
(PARI) a(n) = {my(res = 0);
for(x = 1, sqrtint(n\3), for(y = x + 1, (n - x^2) \ (2 * x), z = (n - x*y) / (x + y); if(z > y && z == z\1, res++))); res} \\ David A. Corneth, Oct 01 2017
|
|
CROSSREFS
|
Cf. A066955 (ways to represent n as n = x*y + y*z + z*x where 0 <= x <= y <= z).
Cf. A094377 (greatest number having exactly n representations).
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|