OFFSET
1,2
COMMENTS
A019434 is a subsequence. - David A. Corneth, Jun 30 2017
Is the frequency of e such that A000005(a(n))^e = A000010(a(n)) finite? - David A. Corneth, Jul 01 2017
LINKS
Charles R Greathouse IV, Table of n, a(n) for n = 1..5319 (first 526 terms from Antti Karttunen)
MATHEMATICA
Join[{1}, Select[Range[2, 5000], IntegerQ[Log[DivisorSigma[0, #], EulerPhi[#]]]&]] (* Harvey P. Dale, Aug 06 2017 *)
PROG
(PARI) ispowerof(n, k)= if(k==1, return(n==1)); while(n>=k, if(n%k!=0, return(0)); n\=k); n==1
isa(n) = ispowerof(eulerphi(n), numdiv(n)) \\ Quick program, fast enough for early values.
(PARI) is(n) = if(n==1, return(1)); my(f = factor(n); phi = eulerphi(f), ndiv = numdiv(f), e = logint(phi, ndiv)); ndiv^e == phi \\ David A. Corneth, Jun 30 2017, changed per suggestion of Charles R Greathouse IV
(PARI) isA289276(n)= if(n==1, return(1)); my(phi = eulerphi(n), ndiv = numdiv(n), v = valuation(phi, ndiv)); ndiv^v == phi; \\ (A variant of above program). - Antti Karttunen, Jun 30 2017
(PARI) list(lim)=my(v=List([1])); forfactored(n=2, lim\1, my(phi = eulerphi(n), ndiv = numdiv(n)); if(ndiv^valuation(phi, ndiv) == phi, listput(v, n[1]))); Vec(v) \\ Charles R Greathouse IV, Jul 01 2017
CROSSREFS
KEYWORD
nonn,nice
AUTHOR
Franklin T. Adams-Watters, Jun 30 2017
STATUS
approved
