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A288507
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Least number k such that both prime(k+1) -/+ prime(k) are products of n prime factors (counting multiplicity).
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1
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OFFSET
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3,1
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COMMENTS
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Prime(k) + prime(k+1) cannot be semiprime, so the offset is 3.
For n=3 to 8, all terms k happen to satisfy prime(k+1) - prime(k) = 2^n. - Michel Marcus, Jul 24 2017
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LINKS
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EXAMPLE
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n = 8: k = 116552943, p = prime(k) = 2394261637, q = prime(k+1) = 2394261893; both q-p = 2^8 and p+q = 2*3^2*5*7^3*155119 are 8-almost primes (A046310).
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PROG
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(PARI) a(n) = my(k = 1, p = 2, q = nextprime(p+1)); while((bigomega(p+q)!= n) || (bigomega(p-q)!= n), k++; p = q; q = nextprime(p+1)); k; \\ Michel Marcus, Jul 24 2017
(Python)
from sympy import factorint, nextprime
k, p, q = 1, 2, 3
while True:
if sum(factorint(q-p).values()) == n and sum(factorint(q+p).values()) == n:
return k
k += 1
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CROSSREFS
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KEYWORD
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nonn,more
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AUTHOR
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STATUS
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approved
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