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A286657
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Triangle read by rows. T(n,k) = least m > 0 such that prime(n) + m * prime(k) and m * prime(n) + prime(k) are both prime numbers, 1 <= k < n.
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1
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1, 1, 2, 3, 2, 2, 1, 4, 6, 6, 3, 2, 2, 4, 6, 1, 2, 4, 2, 4, 2, 5, 4, 2, 4, 8, 4, 14, 3, 10, 4, 2, 4, 6, 12, 6, 1, 10, 6, 6, 4, 14, 6, 8, 6, 5, 4, 2, 4, 2, 4, 24, 18, 14, 8, 3, 10, 2, 6, 6, 10, 6, 4, 2, 6, 10, 1, 4, 6, 20, 6, 14, 4, 2, 6, 4, 2, 6, 9, 8, 6, 4, 6
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OFFSET
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1,3
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COMMENTS
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The triangle T(n,k) begins:
n\k 1 2 3 4 5 6 7 8 9
1:
2: 1
3: 1 2
4: 3 2 2
5: 1 4 6 6
6: 3 2 2 4 6
7: 1 2 4 2 4 2
8: 5 4 2 4 8 4 14
9: 3 10 4 2 4 6 12 6
10: 1 10 6 6 4 14 6 8 6
Assuming Dickson's conjecture, T(n,k) always exists.
T(n,1) is odd.
T(n,k) is even for any k > 1.
A229980(n) = T(n+1, n) for any n > 0.
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LINKS
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EXAMPLE
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prime(7) + m*prime(11) is prime for m = 2, 12, 24, 26, 30, ...
m*prime(7) + prime(11) is prime for m = 8, 14, 18, 24, 30, ...
Hence, T(11,7) = 24.
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PROG
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(PARI) t(n, k) = my (pn=prime(n), pk=prime(k), i=1); while (!isprime(pn+i*pk) || !isprime(i*pn+pk), i++); return (i)
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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