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A285736 a(n) = A285735(n) - A285734(n) = n - 2*A285734(n). 3
1, 0, 1, 0, 1, 0, 3, 2, 3, 0, 1, 0, 1, 0, 5, 4, 3, 4, 7, 0, 1, 0, 3, 2, 3, 0, 1, 0, 1, 0, 3, 2, 5, 0, 7, 2, 7, 0, 5, 2, 3, 0, 1, 0, 1, 0, 5, 4, 3, 8, 7, 0, 7, 8, 3, 4, 5, 0, 1, 0, 1, 0, 3, 2, 3, 0, 1, 0, 1, 0, 3, 2, 3, 0, 1, 0, 1, 0, 3, 2, 3, 0, 1, 0, 1, 0, 5, 4, 3, 4, 15, 0, 1, 0, 11, 10, 5, 4, 7, 6, 9, 0, 11, 2, 11, 0, 15, 2, 7, 0, 5, 2, 3, 0, 1, 0, 1, 0, 3 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,7

LINKS

Antti Karttunen, Table of n, a(n) for n = 1..10000

FORMULA

a(n) = A285735(n) - A285734(n) = n - 2*A285734(n).

PROG

(Scheme)

(define (A285736 n) (- (A285735 n) (A285734 n)))

(define (A285736 n) (- n (* 2 (A285734 n))))

(Python)

from sympy.ntheory.factor_ import core

def issquarefree(n): return core(n) == n

def a285734(n):

    if n==1: return 0

    j=n//2

    while True:

        if issquarefree(j) and issquarefree(n - j): return j

        else: j-=1

def a285736(n): return n - 2*a285734(n)

print([a285736(n) for n in range(1, 101)]) # Indranil Ghosh, May 02 2017

CROSSREFS

Cf. A005117 (2*A005117 gives the positions of zeros), A285734, A285735.

Sequence in context: A016458 A058513 A319650 * A325142 A047160 A332497

Adjacent sequences:  A285733 A285734 A285735 * A285737 A285738 A285739

KEYWORD

nonn

AUTHOR

Antti Karttunen, May 02 2017

STATUS

approved

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Last modified August 14 05:20 EDT 2022. Contains 356110 sequences. (Running on oeis4.)