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A285523
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Numbers n such that n^2 + 1 is 100-smooth
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1
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1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 17, 18, 21, 22, 23, 27, 30, 31, 32, 34, 38, 41, 43, 46, 47, 50, 55, 57, 68, 70, 72, 73, 75, 83, 99, 117, 119, 123, 132, 133, 157, 172, 173, 182, 191, 216, 233, 239, 242, 255, 265, 268, 278, 302, 307, 319, 327, 378, 401, 411, 438, 447
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OFFSET
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1,2
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COMMENTS
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Equivalently: Numbers n such that all prime factors of n^2 + 1 are <= 97.
Since an odd prime factor of n^2 + 1 must be of the form 4m + 1, n^2 + 1 must be of the form 2^t*5^a*13^b*17^c*29^d*37^e*41^f*53^g*61^h*73^i*89^j*97^k, with t = 0 or 1.
Luca determined all terms.
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LINKS
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EXAMPLE
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157^2 + 1 = 2*5^2*17*29 so 157 is a term.
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PROG
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(PARI) isok(n) = vecmax(factor(n^2+1)[, 1]) <= 100; \\ Michel Marcus, Apr 23 2017
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CROSSREFS
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KEYWORD
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nonn,fini,full
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AUTHOR
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STATUS
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approved
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