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A285440
Consider the sums of the numbers < n that share the same greatest common divisor with n. Sequence lists numbers that have only one of those sums equal to n.
0
3, 4, 8, 9, 15, 16, 20, 21, 27, 28, 32, 33, 39, 40, 44, 45, 51, 52, 56, 57, 63, 64, 68, 69, 75, 76, 80, 81, 87, 88, 92, 93, 99, 100, 104, 105, 111, 112, 116, 117, 123, 124, 128, 129, 135, 136, 140, 141, 147, 148, 152, 153, 159, 160, 164, 165, 171, 172, 176, 177
OFFSET
1,1
COMMENTS
Numbers with no sum equal to n are listed in A108118, with two sums equal to n are listed in A017593 and with three sums equal to n in A008594.
First difference has period 4: {1,4,1,6}.
Numbers that are congruent to {3, 4, 8, 9} mod 12. - Amiram Eldar, Dec 31 2021
FORMULA
From Chai Wah Wu, Nov 01 2018: (Start)
a(n) = a(n-1) + a(n-4) - a(n-5) for n > 5.
G.f.: x*(3*x^4 + x^3 + 4*x^2 + x + 3)/(x^5 - x^4 - x + 1). (End)
Sum_{n>=1} (-1)^(n+1)/a(n) = (3-sqrt(3))*Pi/36. - Amiram Eldar, Dec 31 2021
EXAMPLE
20 is in the sequence because:
gcd(k,20) = 1 for k = 1, 3, 7, 9, 11, 13, 17, 19: sum is 80.
gcd(k,20) = 2 for k = 2, 6, 14, 18: sum is 40.
gcd(k,20) = 4 for k = 4, 8, 12, 16: sum is 40.
gcd(k,20) = 5 for k = 5, 15: sum is 20.
gcd(k,20) = 10 for k = 10: sum is 10.
MAPLE
P:=proc(q) local a, k, n, t;
for n from 1 to q do a:=array(1..n-1); for k from 1 to n-1 do a[k]:=0; od;
for k from 1 to n-1 do a[gcd(n, k)]:=a[gcd(n, k)]+k; od; t:=0;
for k from 1 to n-1 do if a[k]=n then t:=t+1; fi; od; if t=1 then print(n); fi;
od; end: P(10^6);
MATHEMATICA
Flatten@ Position[#, k_ /; Length@ k == 1] &@ Table[Select[Transpose@ {Values@ #, Keys@ #} &@ Map[Total, PositionIndex@ Map[GCD @@ {n, #} &, Range[n - 1]]], First@ # == n &][[All, -1]], {n, 180}] (* Michael De Vlieger, Apr 28 2017, Version 10 *)
LinearRecurrence[{1, 0, 0, 1, -1}, {3, 4, 8, 9, 15}, 60] (* Amiram Eldar, Dec 31 2021 *)
PROG
(PARI) a(n) = n--; [3, 4, 8, 9][n%4+1] + 12*(n\4) \\ David A. Corneth, Apr 28 2017
(PARI) is(n) = {my(d=divisors(n), map=vector(d[#d-1]), v=vector(#d-1)); for(i=1, #d-1, map[d[i]]=i); for(i=1, n-1, v[map[gcd(i, n)]]+=i); sum(i=1, #v, v[i]==n)==1} \\ David A. Corneth, Apr 28 2017
(PARI) is(n) = vecsort(concat([3, 4, 8, 9], [n%12]), , 8)==[3, 4, 8, 9] \\ David A. Corneth, Apr 28 2017
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Paolo P. Lava, Apr 19 2017
STATUS
approved