OFFSET
1,4
COMMENTS
The number of exponential unitary (or e-unitary) divisors of n and the number of exponential squarefree exponential divisors (or e-squarefree e-divisors) of n. These are divisors of n = Product p(i)^a(i) of the form Product p(i)^b(i) where each b(i) is a unitary divisor of a(i) in the first case, or each b(i) is a squarefree divisor of a(i) in the second case. - Amiram Eldar, Dec 29 2018
The number of exponential divisors (A322791) of n that are exponentially squarefree numbers (A209061). - Amiram Eldar, Jan 13 2026
LINKS
Antti Karttunen, Table of n, a(n) for n = 1..10000
Xiaodong Cao and Wenguang Zhai, Some arithmetic functions involving exponential divisors, Journal of Integer Sequences, Vol. 13 (2010), Article 10.3.7, eq (20).
Nicuşor Minculete and László Tóth, Exponential unitary divisors, Annales Univ. Sci. Budapest., Sect. Comp., Vol. 35 (2011), pp. 205-216.
Y. F. S. Pétermann, Arithmetical functions involving exponential divisors: Note on two papers by L. Tóth, Annales Univ. Sci. Budapest., Sect. Comp., Vol. 32 (2010), pp. 143-149. See Theorem A, p. 144.
László Tóth, On certain arithmetic functions involving exponential divisors, II, Annales Univ. Sci. Budapest., Sect. Comp., Vol. 27 (2007), pp. 155-166; arXiv preprint, arXiv:0708.3557 [math.NT], 2007-2009.
Xiangzhen Zhao, Min Liu, and Yu Huang, Mean value for the function t^(e)(n) over square-full numbers, Scientia Magna, Vol. 8, No. 3 (2012), pp. 110-114.
FORMULA
Asymptotic mean: lim_{n->oo} (1/n) * Sum_{k=1..n} a(k) = Product_{p prime} (1 + Sum_{k>=2} (2^omega(k) - 2^omega(k-1))/p^k) = 1.5431653193... (A393489) (Tóth, 2007). - Amiram Eldar, Nov 08 2020
More precisely, Sum_{k=1..n} a(k) = C_1 * n + C_2 * sqrt(n) + O(n^(1/4+eps)), where C_1 = A393489 and C_2 = zeta(1/2) * Product_{p prime} (1 + Sum_{k>=4} (2^omega(k) - 2^omega(k-1) - 2^omega(k-2) + 2^omega(k-3))/p^(k/2)) = -0.99308863474918955038... (Pétermann, 2010). - Amiram Eldar, Mar 17 2026
MAPLE
MATHEMATICA
Table[Times @@ Apply[Times, FactorInteger[n] /. {p_, e_} /; p > 1 :> 2^PrimeNu[e]], {n, 105}] (* Michael De Vlieger, Jul 29 2017 *)
PROG
(Scheme) (define (A278908 n) (if (= 1 n) n (* (A000079 (A001221 (A067029 n))) (A278908 (A028234 n))))) ;; Antti Karttunen, Jul 27 2017
(PARI) a(n) = my(f=factor(n)); for (k=1, #f~, f[k, 1] = 2^omega(f[k, 2]); f[k, 2] = 1); factorback(f); \\ Michel Marcus, Jul 28 2017
(Python)
from sympy.functions.combinatorial.numbers import primenu, factorint
def A278908(n): return 1<<sum(map(primenu, factorint(n).values())) # Chai Wah Wu, Oct 18 2025
CROSSREFS
KEYWORD
nonn,easy,mult
AUTHOR
R. J. Mathar, Nov 30 2016
STATUS
approved
