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A277676
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Numbers k such that d(k+2) > d(k+1), where d(m) is the number of digits in the base-m representation of m!.
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3
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2, 4, 5, 6, 8, 9, 10, 12, 13, 14, 16, 17, 18, 20, 21, 22, 23, 25, 26, 27, 29, 30, 31, 32, 34, 35, 36, 37, 39, 40, 41, 42, 44, 45, 46, 47, 49, 50, 51, 52, 53, 55, 56, 57, 58, 60, 61, 62, 63, 65, 66, 67, 68, 69, 71, 72, 73, 74, 76, 77, 78, 79, 80, 82, 83, 84
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OFFSET
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1,1
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COMMENTS
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It has been checked for k = 2..50000 that if d(k+1) > d(k), then d(k+1) = d(k) + 1.
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LINKS
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FORMULA
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MATHEMATICA
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d = Differences@Array[Floor@Log[#, #!] &, 10000, 2]; (* Robert G. Wilson v, Oct 27 2016 *)
u = Flatten[Position[d, 0]]; (* A277675 *)
v = Flatten[Position[d, 1]]; (* A277676 *)
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PROG
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(PARI) d(n) = #digits(n!, n);
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CROSSREFS
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KEYWORD
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nonn,base,easy
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AUTHOR
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STATUS
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approved
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