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A276793
Indicator function for A003144.
7
1, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0
OFFSET
1
COMMENTS
a(n) = 1 iff n is a term of A003144.
The binary complement of (a(n)) is called the "binary Tribonacci word" in Mousavi and Shallit (see Theorem 23). It is defined to be the change of alphabet {0,1,2} -> {0,1,1} of the tribonacci word 0102010010... - Michel Dekking, Oct 12 2019
LINKS
Wolfdieter Lang, The Tribonacci and ABC Representations of Numbers are Equivalent, arXiv preprint arXiv:1810.09787 [math.NT], 2018.
Hamoon Mousavi and Jeffrey Shallit, Mechanical Proofs of Properties of the Tribonacci Word, arXiv:1407.5841 [cs.FL], 2014.
H. Mousavi and J. Shallit, Mechanical Proofs of Properties of the Tribonacci Word, In: Manea F., Nowotka D. (eds) Combinatorics on Words. WORDS 2015. Lecture Notes in Computer Science, vol 9304. Springer, 2015, pp. 170-190.
FORMULA
a(n) = (A080843(n-1)-1)*(A080843(n-1)-2)/2. - Wolfdieter Lang, Dec 06 2018
CROSSREFS
A276793(n) + A276794(n) + A276791(n) = 1; A276796(n) + A276797(n) + A276798(n) = n+1.
Sequence in context: A162549 A191188 A285592 * A375349 A284364 A115788
KEYWORD
nonn,easy
AUTHOR
N. J. A. Sloane, Oct 28 2016
EXTENSIONS
Data and offset changed by Michel Dekking, Oct 12 2019
STATUS
approved