OFFSET
1,1
COMMENTS
From Omar E. Pol, Dec 21 2021: (Start)
For a visualization of T(n,j) first consider a tower (a polycube) in which the terraces are the symmetric representation of sigma(j), for j = 1 to n, starting from the top, and the heights of the terraces are the first n prime numbers respectively starting from the base. Then T(n,j) can be represented with a set of A237271(j) right prisms of height A000040(n-j+1) since T(n,j) is also the total number of cubes that are exactly below the parts of the symmetric representation of sigma(j) in the tower.
The sum of the n-th row of triangle is A086718(n) equaling the volume of the tower whose largest side of the base is n and its total height is the n-th prime.
LINKS
Ivan Neretin, Table of n, a(n) for n = 1..8128
FORMULA
EXAMPLE
The corner of the square array begins:
2, 6, 8, 14, 12, 24, 16, 30, 26, 36, ...
3, 9, 12, 21, 18, 36, 24, 45, 39, 54, ...
5, 15, 20, 35, 30, 60, 40, 75, 65, 90, ...
7, 21, 28, 49, 42, 84, 56, 105, 91, 126, ...
11, 33, 44, 77, 66, 132, 88, 165, 143, 198, ...
13, 39, 52, 91, 78, 156, 104, 195, 169, 234, ...
17, 51, 68, 119, 102, 204, 136, 255, 221, 306, ...
19, 57, 76, 133, 114, 228, 152, 285, 247, 342, ...
23, 69, 92, 161, 138, 276, 184, 345, 299, 414, ...
29, 87, 116, 203, 174, 348, 232, 435, 377, 522, ...
...
From Omar E. Pol, Dec 21 2021: (Start)
Written as a triangle the sequence begins:
2;
3, 6;
5, 9, 8;
7, 15, 12, 14;
11, 21, 20, 21, 12;
13, 33, 28, 35, 18, 24;
17, 39, 44, 49, 30, 36, 16;
19, 51, 52, 77, 42, 60, 24, 30;
23, 57, 68, 91, 66, 84, 40, 45, 26;
29, 69, 76, 119, 78, 132, 56, 75, 39, 36;
31, 87, 92, 133, 102, 156, 88, 105, 65, 54, 24;
...
Row sums give A086718. (End)
MATHEMATICA
Table[Prime[#] DivisorSigma[1, k] &@(n - k + 1), {n, 12}, {k, n}] // Flatten (* Michael De Vlieger, Apr 28 2016 *)
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Omar E. Pol, Apr 28 2016
STATUS
approved