OFFSET
1,1
COMMENTS
EXAMPLE
Triangle begins:
3;
9;
15, 3;
21, 0;
27, 9;
33, 0, 3;
39, 15, 0;
45, 0, 0;
51, 21, 9;
57, 0, 0, 3;
63, 27, 0, 0;
69, 0, 15, 0;
75, 33, 0, 0;
81, 0, 0, 9;
87, 39, 21, 0, 3;
93, 0, 0, 0, 0;
99, 45, 0, 0, 0;
105, 0, 27, 15, 0;
111, 51, 0, 0, 0;
117, 0, 0, 0, 9;
123, 57, 33, 0, 0, 3;
129, 0, 0, 21, 0, 0;
135, 63, 0, 0, 0, 0;
141, 0, 39, 0, 0, 0;
...
For n = 9 the divisors of 9 are 1, 3, 9, therefore the sum of the divisors of 9 is 1 + 3 + 9 = 13 and 3*13 = 39. On the other hand the 9th row of triangle is 51, 21, 9, therefore the alternating row sum is 51 - 21 + 9 = 39, equaling 3 times sigma(9).
CROSSREFS
KEYWORD
nonn,tabf
AUTHOR
Omar E. Pol, Apr 18 2016
STATUS
approved