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A239662
Triangle read by rows: T(n,k), n>=1, k>=1, in which column k lists the numbers A017113 interleaved with k-1 zeros, and the first element of column k is in row k(k+1)/2.
5
4, 12, 20, 4, 28, 0, 36, 12, 44, 0, 4, 52, 20, 0, 60, 0, 0, 68, 28, 12, 76, 0, 0, 4, 84, 36, 0, 0, 92, 0, 20, 0, 100, 44, 0, 0, 108, 0, 0, 12, 116, 52, 28, 0, 4, 124, 0, 0, 0, 0, 132, 60, 0, 0, 0, 140, 0, 36, 20, 0, 148, 68, 0, 0, 0, 156, 0, 0, 0, 12, 164, 76, 44, 0, 0, 4, 172, 0, 0, 28, 0, 0, 180, 84, 0, 0, 0, 0, 188, 0, 52, 0, 0, 0
OFFSET
1,1
COMMENTS
Gives an identity for A239050. Alternating sum of row n equals A239050(n), i.e., Sum_{k=1..A003056(n)} (-1)^(k-1)*T(n,k) = 4*A000203(n) = 2*A074400(n) = A239050(n).
Row n has length A003056(n) hence the first element of column k is in row A000217(k).
Note that if T(n,k) = 12 then T(n+1,k+1) = 4, the first element of the column k+1.
The number of positive terms in row n is A001227(n).
For more information see A196020.
Column 1 is A017113. - Omar E. Pol, Apr 17 2016
FORMULA
T(n,k) = 2*A236106(n,k) = 4*A196020(n,k).
EXAMPLE
Triangle begins:
4;
12;
20, 4;
28, 0;
36, 12;
44, 0, 4;
52, 20, 0;
60, 0, 0;
68, 28, 12;
76, 0, 0, 4;
84, 36, 0, 0;
92, 0, 20, 0;
100, 44, 0, 0;
108, 0, 0, 12;
116, 52, 28, 0, 4;
124, 0, 0, 0, 0;
132, 60, 0, 0, 0;
140, 0, 36, 20, 0;
148, 68, 0, 0, 0;
156, 0, 0, 0, 12;
164, 76, 44, 0, 0, 4;
172, 0, 0, 28, 0, 0;
180, 84, 0, 0, 0, 0;
188, 0, 52, 0, 0, 0;
...
For n = 9, the 9th row of triangle is [68, 28, 12], therefore the alternating row sum is 68 - 28 + 12 = 52. On the other hand we have that 4*A000203(9) = 2*A074400(9) = A239050(9) = 4*13 = 2*26 = 52, equaling the alternating sum of the 9th row of the triangle.
KEYWORD
nonn,tabf
AUTHOR
Omar E. Pol, Mar 30 2014
STATUS
approved