A265330 Zero-based row index to A265345; 2-adic valuation of bijective base-3 reversal of n: a(n) = A007814(A263273(n)).

0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 4, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 6, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 4, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 5, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 4, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 6, 0, 1, 0, 2, 0, 1, 0, 4, 0, 1, 0, 2, 0, 1, 0, 4, 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 3

Offset

1,4

Links

Antti Karttunen, Table of n, a(n) for n = 1..6561

Formula

a(n) = A007814(A263273(n)).

a(2n+1) = 0, a(2n) = 1 + a(A265352(n)).

Example

For n = 32, in base-3 "1012" [= A007089(32)], when we reverse it, we get "2101" [= A007089(64)], and 2-adic valuation of 64 [= "1000000" = A007088(64)] is 6, thus a(32) = 6.

Prog

(Scheme, two variants)
(definec (A265330 n) (if (odd? n) 0 (+ 1 (A265330 (A265352 (/ n 2))))))
(define (A265330 n) (A007814 (A263273 n)))

Crossrefs

One less than A265331.

Cf. A007088, A007089, A263273, A265345, A265352.

Cf. A265910 (corresponding other index).

Cf. also A265336, A265337, A265340.

Differs from A007814 for the first time at n=32, where a(32) = 6, while A007814(32) = 5.

Sequence in context: A254990 A191255 A007814 * A272216 A349906 A320439

Adjacent sequences: A265327 A265328 A265329 * A265331 A265332 A265333

Keyword

nonn,base

Author

Antti Karttunen, Dec 18 2015

Status

approved