A263361 Expansion of Product_{k>=1} 1/(1-x^(k+5))^k.

1, 0, 0, 0, 0, 0, 1, 2, 3, 4, 5, 6, 8, 10, 15, 20, 30, 40, 58, 76, 106, 140, 191, 252, 344, 454, 613, 814, 1091, 1442, 1926, 2538, 3368, 4432, 5852, 7678, 10107, 13222, 17337, 22636, 29582, 38518, 50195, 65198, 84712, 109784, 142254, 183924, 237742, 306688

Offset

0,8

Links

Vaclav Kotesovec, Table of n, a(n) for n = 0..5000

Vaclav Kotesovec, A method of finding the asymptotics of q-series based on the convolution of generating functions, arXiv:1509.08708 [math.CO], Sep 30 2015

Formula

G.f.: exp(Sum_{k>=1} x^(6*k)/(k*(1-x^k)^2).

a(n) ~ exp(1/12 - 25*Pi^4/(432*Zeta(3)) - 5*Pi^2 * n^(1/3) / (3 * 2^(4/3) * Zeta(3)^(1/3)) + 3 * 2^(-2/3) * Zeta(3)^(1/3) * n^(2/3)) * n^(125/36) * Pi^2 / (576 * A * 2^(35/36) * sqrt(3) * Zeta(3)^(143/36)), where Zeta(3) = A002117 and A = A074962 is the Glaisher-Kinkelin constant.

Maple

with(numtheory):
a:= proc(n) option remember; `if`(n=0, 1, add(add(d*
      max(0, d-5), d=divisors(j))*a(n-j), j=1..n)/n)
    end:
seq(a(n), n=0..50);  # Alois P. Heinz, Oct 16 2015

Mathematica

nmax = 60; CoefficientList[Series[Product[1/(1-x^(k+5))^k, {k, 1, nmax}], {x, 0, nmax}], x]
nmax = 60; CoefficientList[Series[E^Sum[x^(6*k)/(k*(1-x^k)^2), {k, 1, nmax}], {x, 0, nmax}], x]

Crossrefs

Cf. A000219, A052847, A263358, A263359, A263360, A263362, A263363, A263364.

Sequence in context: A218949 A129976 A105181 * A320020 A229034 A265406

Adjacent sequences: A263358 A263359 A263360 * A263362 A263363 A263364

Keyword

nonn

Author

Vaclav Kotesovec, Oct 16 2015

Status

approved