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A263081
a(n) = largest k for which A155043(k) < A262508(n); a(n) = A262509(n) + A262909(n).
5
124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 124340, 24684000, 24684000, 24684000, 24684000, 24684000, 24684000, 24684000
OFFSET
1,1
COMMENTS
a(n) = largest k for which A155043(k) < A155043(A262509(n)).
If a(n) > A262509(n) then it must be a leaf (see comments in A262909 for why). Particularly, we have A045765(40722) = 124340, A045765(8191770) = 24684000.
Terms of sequence (together with the corresponding values in A262508) give particularly clean values for the boundaries that are used for example in the C++-program which computes A262896.
LINKS
FORMULA
a(n) = A263077(A262509(n)).
a(n) = A262509(n) + A262909(n).
PROG
(Scheme) (define (A263081 n) (+ (A262509 n) (A262909 n)))
KEYWORD
nonn
AUTHOR
Antti Karttunen, Oct 09 2015
STATUS
approved