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A262882
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Right diagonal of A262881.
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1
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0, 1, 2, 3, 3, 5, 6, 7, 7, 7, 7, 11, 11, 13, 14, 15, 15, 15, 15, 15, 15, 15, 15, 23, 23, 23, 23, 27, 27, 29, 30, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 47, 47, 47, 47, 47, 47, 47, 47, 55, 55, 55, 55, 59, 59, 61, 62, 63, 63, 63, 63, 63
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OFFSET
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0,3
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COMMENTS
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It appears that the sequence of unique terms is A089633, and that their run lengths are 1, 1, 1, 2, 1, 1, 4, 2, 1, 1, 8, ...: A155038.
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LINKS
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MATHEMATICA
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Last /@ Table[SortBy[Range@ k, And[Total@ IntegerDigits[#, 2], k] &], {k, 67}] (* Michael De Vlieger, Oct 04 2015 *)
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PROG
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(PARI) cmph(i, j) = if (hammingweight(i) != hammingweight(j), hammingweight(i) - hammingweight(j), i - j);
row(n) = my(v = vector(n+1, k, k-1)); vecsort(v, cmph);
lista(nn) = {for (n=0, nn, my(r = srow(n)); print1(r[#r], ", "); ); }
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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