OFFSET
1,2
COMMENTS
Remainder when product of first n odd primes is divided by sum of first n odd primes.
Obviously a(2n) cannot be 0. Does 0 appear in the sequence infinitely often?
EXAMPLE
a(1) = prime(2) mod prime(2) = 3 mod 3 = 0.
a(2) = (prime(2) * prime(3)) mod (prime(2) + prime(3)) = 15 mod 8 = 7.
a(3) = (prime(2) * prime(3) * prime(4)) mod (prime(2) + prime(3) + prime(4)) = 105 mod 15 = 0.
a(4) = (prime(2) * prime(3) * prime(4) * prime(5)) mod (prime(2) + prime(3) + prime(4) + prime(5)) = 1155 mod 26 = 11.
MATHEMATICA
Table[Mod[Product[Prime[k + 1], {k, n}], Sum[Prime[k + 1], {k, n}]], {n, 60}] (* Michael De Vlieger, Oct 02 2015 *)
PROG
(PARI) a(n) = prod(k=1, n, prime(k+1)) % sum(k=1, n, prime(k+1));
vector(60, n, a(n))
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Altug Alkan, Oct 02 2015
STATUS
approved