A257893 Pandigital numbers reordered so that the numbers A050278(n)/2^k, where 2^k||A050278(n), appear in nondecreasing order.

3076521984, 3718250496, 6398410752, 1384906752, 2769813504, 2845310976, 1578369024, 1074659328, 4761059328, 9805234176, 2507931648, 1294073856, 5619843072, 6591873024, 9073852416, 9574023168, 1208549376, 1249837056, 6103498752, 1542389760, 1683947520

Offset

1,1

Comments

If two such numbers A050278(n_1)/2^k_1 and A050278(n_2)/2^k_2 are equal, then A050278(n_1) appears earlier than A050278(n_2) iff A050278(n_1)<A050278(n_2). For example, a(4)/2^18=a(5)/2^19=5283.

There are 184423 such pairs.

Links

Chai Wah Wu, Table of n, a(n) for n = 1..1000

Formula

min(A050278(n)/2^k) = 3076521984/2^21 = 1467.

Prog

(Python)
from itertools import permutations
l = []
for d in permutations('0123456789', 10):
....if d[0] != '0':
........d2 = int(''.join(d))
........d = d2
........r = d2 % 2
........while not r:
............d2, r = divmod(d2, 2)
........l.append((d2, d))
l.sort()
A257893_list = [b for a, b in l] # Chai Wah Wu, May 24 2015

Crossrefs

Cf. A050278.

Sequence in context: A225140 A203886 A257914 * A015397 A291600 A092380

Adjacent sequences: A257890 A257891 A257892 * A257894 A257895 A257896

Keyword

nonn,base,fini

Author

Vladimir Shevelev and Peter J. C. Moses, May 12 2015

Status

approved