A255337 After a(0) = 0, the first differences of A255057: for n >= 1: a(n) = A255057(n) - A255057(n-1).

0, 1, 1, 1, 2, 1, 1, 2, 2, 2, 1, 1, 1, 2, 3, 2, 2, 2, 2, 1, 1, 1, 2, 3, 2, 3, 3, 2, 1, 2, 3, 2, 2, 2, 2, 1, 1, 1, 2, 3, 2, 3, 2, 2, 3, 3, 3, 3, 3, 2, 1, 2, 3, 2, 3, 3, 2, 1, 2, 3, 2, 2, 2, 2, 1, 1, 1, 2, 3, 2, 3, 2, 2, 3, 3, 3, 3, 2, 2, 3, 3, 3, 4, 3, 3, 3, 3, 3, 3, 2, 1, 2, 3, 2, 3, 2, 2, 3, 3, 3, 3, 3, 2, 1, 2, 3, 2, 3, 3, 2, 1, 2, 3, 2, 2, 2, 2, 1, 1

Offset

0,5

Comments

Used for computing A255338 and A255339.

Links

Antti Karttunen, Table of n, a(n) for n = 0..8590

Formula

a(n) = A005811(A255056(n))/2.

a(0) = 0; and for n >= 1: a(n) = A255057(n) - A255057(n-1).

a(n) = A255336(n)/2.

Prog

(Scheme, two versions)
(define (A255337 n) (/ (A005811 (A255056 n)) 2))
(define (A255337 n) (if (zero? n) n (- (A255057 n) (A255057 (- n 1)))))

Crossrefs

First differences of A255057.

Terms of A255336 divided by 2.

Cf. A005811, A213712, A255338, A255339.

Sequence in context: A217463 A109073 A341694 * A026465 A051486 A218541

Adjacent sequences: A255334 A255335 A255336 * A255338 A255339 A255340

Keyword

nonn

Author

Antti Karttunen, Feb 21 2015

Status

approved