A248185 Numbers k such that A248183(k+1) = A248183(k) + 1.

3, 4, 6, 7, 9, 10, 11, 13, 14, 16, 17, 19, 20, 21, 23, 24, 26, 27, 28, 30, 31, 33, 34, 36, 37, 38, 40, 41, 43, 44, 45, 47, 48, 50, 51, 53, 54, 55, 57, 58, 60, 61, 62, 64, 65, 67, 68, 69, 71, 72, 74, 75, 77, 78, 79, 81, 82, 84, 85, 86, 88, 89, 91, 92, 94, 95

Offset

1,1

Links

Clark Kimberling, Table of n, a(n) for n = 1..1000

Example

The difference sequence of A248183 is (0, 0, 1, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1,...), so that A248184 = (1, 2, 5, 8, 12, 15, 18, 22,...) and A248185 = (3, 4, 6, 7, 9, 10, 11, 13, 14, 16, 17,...), the complement of A248184.

Mathematica

z = 200; p[k_] := p[k] = Sum[1/(h*(h + 1)*(h + 2)), {h, 1, k}] ;
N[Table[1/4 - p[n], {n, 1, z/10}]]
f[n_] := f[n] = Select[Range[z], 1/4 - p[#] < 1/n^2 &, 1];
u = Flatten[Table[f[n], {n, 1, z}]]   (* A248183 *)
Flatten[Position[Differences[u], 0]]  (* A248184 *)
Flatten[Position[Differences[u], 1]]  (* A248185 *)

Crossrefs

Cf. A248183, A248184.

Sequence in context: A183860 A298109 A184429 * A357504 A130269 A290730

Adjacent sequences: A248182 A248183 A248184 * A248186 A248187 A248188

Keyword

nonn,easy

Author

Clark Kimberling, Oct 04 2014

Status

approved