A247883 Consecutive exclusionary cubes: Digits of n are not present in n^3 and digits of n+1 are not present in n+1.

2, 7, 47, 52, 187, 222, 477, 587, 5522, 6777

Offset

1,1

Comments

If it exists, a(11) > 10^7.

Links

Table of n, a(n) for n=1..10.

Prog

(Python)
for n in range(10**6):
..s, t = str(n), str(n+1)
..s3, t3 = str(n**3), str((n+1)**3)
..c = 0
..for i in s:
....if s3.count(i):
......c += 1
......break
..for j in t:
....if t3.count(j):
......c += 1
......break
..if not c:
....print(n, end=', ')
(PARI)
for(n=1, 10^6, s=digits(n); t=digits(n+1); s3=digits(n^3); t3=digits((n+1)^3); if(#vecsort(concat(s, s3), , 8)==#vecsort(s, , 8)+#vecsort(s3, , 8)&&#vecsort(concat(t, t3), , 8)==#vecsort(t, , 8)+#vecsort(t3, , 8), print1(n, ", ")))

Crossrefs

Cf. A029785.

Sequence in context: A351917 A349640 A111842 * A027458 A062632 A116892

Adjacent sequences: A247880 A247881 A247882 * A247884 A247885 A247886

Keyword

nonn,base

Author

Derek Orr, Sep 25 2014

Status

approved