OFFSET
1,1
COMMENTS
For n > 24, a(n) = a(n-24) + 111111.
If j is of form 3m+1 then j*10^k-1 is always divisible by 3. - Jens Kruse Andersen, Jul 09 2014
LINKS
Andrew Howroyd, Table of n, a(n) for n = 1..1000
Index entries for linear recurrences with constant coefficients, signature (1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,-1).
FORMULA
a(n) = a(n-24) + 111111 for n > 24.
EXAMPLE
10176*10^k-1 is divisible by 11 for k of form 6m, 6m+2, 6m+4, by 7 for k of form 6m+1, by 37 for 6m+3 (and also 6m), and by 13 for 6m+5. This covers all k. {7, 11, 13, 37} is called a covering set. - Jens Kruse Andersen, Jul 09 2014
PROG
(PFGW)
SCRIPT
DIM k, 0
DIM n
DIMS t
OPENFILEOUT myf, res.txt
LABEL loop1
SET k, k+1
SET n, 0
LABEL loop2
SET n, n+1
IF n>500 THEN GOTO a
IF (k*10^n-1)%7==0 THEN GOTO loop2
IF (k*10^n-1)%11==0 THEN GOTO loop2
IF (k*10^n-1)%13==0 THEN GOTO loop2
IF (k*10^n-1)%37==0 THEN GOTO loop2
GOTO loop1
LABEL a
WRITE myf, k
PRINT k
GOTO loop1
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Pierre CAMI, Jun 16 2014
EXTENSIONS
Definition corrected by Jens Kruse Andersen, Jul 09 2014
a(25) onward from Andrew Howroyd, Feb 08 2026
STATUS
approved
