1,1

It appears that starting from a(64)=104 on, the sequence consists exactly in the numbers (larger than 103) congruent to 2 mod 3.

Table of n, a(n) for n=1..81.

For n >= 64, a(n) = 3n - 88. (Conjectured.)

(PARI) m=0; for(i=1, 1000, m<(m=max(A112801(i), m))&&print1(i", "))

Sequence in context: A015877 A192290 A152010 * A046085 A054296 A155704

Adjacent sequences: A243747 A243748 A243749 * A243751 A243752 A243753

nonn

M. F. Hasler, Jun 09 2014

approved