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A240950
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Numbers k such that the continued fraction for sqrt(k) has odd period, omitting those values of k of the form m^2+1.
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1
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13, 29, 41, 53, 58, 61, 73, 74, 85, 89, 97, 106, 109, 113, 125, 130, 137, 149, 157, 173, 181, 185, 193, 202, 218, 229, 233, 241, 250, 265, 269, 274, 277, 281, 293, 298, 313, 314, 317, 337, 338, 346, 349, 353, 365, 370, 373, 389, 394, 397, 409, 421, 425, 433
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OFFSET
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1,1
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COMMENTS
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p^2 - n*q^2 = -1 is solvable for integers p and q.
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LINKS
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EXAMPLE
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sqrt(13) = [3;1,1,1,1,6].
sqrt(29) = [5;2,1,1,2,10].
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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