

A238325


Array: row n gives the number of occurrences of each possible antidiagonal partition of n, arranged in reverseMathematica order.


7



1, 2, 2, 1, 2, 3, 2, 2, 3, 2, 2, 6, 1, 2, 2, 4, 3, 4, 2, 2, 4, 6, 2, 6, 2, 2, 4, 4, 2, 3, 9, 4, 2, 2, 4, 4, 2, 6, 6, 3, 12, 1, 2, 2, 4, 4, 2, 4, 6, 3, 6, 6, 12, 5, 2, 2, 4, 4, 2, 4, 6, 6, 4, 6, 3, 18, 2, 4, 10, 2, 2, 4, 4, 2, 4, 6, 4, 4, 6, 3, 6, 12, 2, 6
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OFFSET

1,2


COMMENTS

Suppose that p is a partition of n, let F(p) be its Ferrers matrix, as defined at A237981, and let mXm be the size of F(p). The numbers of 1's in each of the 2m1 antidiagonals of F(p) form a partition of n. Any partition which is associated with a partition of n in this manner is introduced here as an antidiagonal partition of n. A000041(n) = sum of the numbers in row n; A000009(n) = number of terms in row n, since the antidiagonal partitions of n are the conjugates of the strict partitions of n.


LINKS

Clark Kimberling, Table of n, a(n) for n = 1..1000
Clark Kimberling and Peter J. C. Moses, Ferrers Matrices and Related Partitions of Integers


EXAMPLE

The Mathematica ordering of the 6 antidiagonal partitions of 8 follows: 3221, 32111, 22211, 221111, 2111111, 11111111.) Frequencies of these among the 22 partitions of 8 are given in reverse Mathematica ordering as follows: 11111111 occurs 2 times, 2111111 occurs 2 times, 221111 occurs 4 times, 22211 occurs 6 times, 32111 occurs 2 times, and 3221 occurs 6 times, so that row 8 of the array is 2 2 4 6 2 6.
...
First 12 rows:
1
2
2 1
2 3
2 2 3
2 2 6 1
2 2 4 3 4
2 2 4 6 2 6
2 2 4 4 2 3 9 1
2 2 4 4 2 6 6 3 12 1
2 2 4 4 2 4 6 3 6 6 12 5
2 2 4 4 2 4 6 6 4 6 3 18 2 4 10


MATHEMATICA

z = 20; ferrersMatrix[list_] := PadRight[Map[Table[1, {#}] &, #], {#, #} &[Max[#, Length[#]]]] &[list]; antiDiagPartNE[list_] := Module[{m = ferrersMatrix[list]}, Map[Diagonal[Reverse[m], #] &, Range[#, #] &[Length[m]  1]]]; a1[n_] := Last[Transpose[Tally[Map[DeleteCases[Reverse[Sort[Map[Count[#, 1] &, antiDiagPartNE[#]]]], 0] &, IntegerPartitions[n]]]]];
t = Table[a1[n], {n, 1, z}]; TableForm[Table[a1[n], {n, 1, z}]] (* A238325, array *)
u = Flatten[t] (* A238325, sequence *)
(* Peter J. C. Moses, 18 February 2014 *)


CROSSREFS

Cf. A238326.
Sequence in context: A335424 A270073 A027348 * A238885 A023566 A090970
Adjacent sequences: A238322 A238323 A238324 * A238326 A238327 A238328


KEYWORD

nonn,tabf,easy


AUTHOR

Clark Kimberling and Peter J. C. Moses, Feb 24 2014


STATUS

approved



