OFFSET
1,2
COMMENTS
The number k(n) = log_tau(n) (sigma(n)) = log(sigma(n)) / log(tau(n)) is such that tau(n)^k(n) = sigma(n).
Conjecture: every natural number n has a unique value of k(n). [The conjecture is wrong: e.g., k(5) = k(22) = log(6)/log(2). - Amiram Eldar, Jan 17 2021]
See A236021 - sequence of numbers a(n) such that a(n) > a(k) for all k < n.
LINKS
Michel Marcus, Table of n, a(n) for n = 1..1288
EXAMPLE
For number 1; k(1) = 1.
For number 2; k(2) = log_tau(2) (sigma(2)) = log_2 (3) = 1.5849625007... = A020857.
MATHEMATICA
A[nn_] := Ordering[ N[ Join[ {1}, Table[ Log[DivisorSigma[0, i], DivisorSigma[1, i]], {i, 2, nn} ] ] ] ];
A236020[nn_] := A[nn^2][[1 ;; nn]];
A236020[59] (* Robert P. P. McKone, Jan 17 2021 *)
PROG
(PARI) \\ warning: does not generate all the terms up to nn
f(k) = if (k==1, 1, log(sigma(k)) / log(numdiv(k)));
lista(nn) = vecsort(vector(nn, k, f(k)), , 1); \\ Michel Marcus, Jan 16 2021
CROSSREFS
KEYWORD
nonn
AUTHOR
Jaroslav Krizek, Jan 18 2014
STATUS
approved