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A228845
Least m such that (2k+1)*2^m + 1 is a prime factor of the Fermat number 2^(2^n) + 1.
2
1, 2, 4, 8, 16, 7, 8, 9, 11, 11, 12, 13, 14
OFFSET
0,2
COMMENTS
a(n) >= n + 2 for n >= 2.
a(n) = A228846(n) if 2^(2^n) + 1 is prime or semiprime.
LINKS
Wilfrid Keller, Fermat factoring status
Eric Weisstein's World of Mathematics, Fermat Number
CROSSREFS
KEYWORD
nonn,hard,more
AUTHOR
STATUS
approved